32x^2-30=0

Solution for 32x^2-30=0 equation:

32x^2-30=0

a = 32; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·32·(-30)
Δ = 3840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3840}=\sqrt{256*15}=\sqrt{256}*\sqrt{15}=16\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{15}}{2*32}=\frac{0-16\sqrt{15}}{64}
=-\frac{16\sqrt{15}}{64}
=-\frac{\sqrt{15}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{15}}{2*32}=\frac{0+16\sqrt{15}}{64}
=\frac{16\sqrt{15}}{64}
=\frac{\sqrt{15}}{4}
$